A particle of charge q and mass m is moving with a velocity -vi (v ≠ 0) towards a large screen placed in the Y-Z plane at a distance d. If there is a magnetic field B = B?k, the minimum value of v for which the particle will not hit the screen is:
A particle of charge q and mass m is moving with a velocity -vi (v ≠ 0) towards a large screen placed in the Y-Z plane at a distance d. If there is a magnetic field B = B?k, the minimum value of v for which the particle will not hit the screen is:
Option 1 -
q²B₀/3m
Option 2 -
2qdB₀/m
Option 3 -
qdB₀/m
Option 4 -
qdB₀/2m
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:r = mv/qB?
To not collide, r∴ Vmax = qB? d/m
Note: It should be maximum instead of minimum.
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