An infinitely long straight conductor carries a current of $5\mathrm{A}$ as shown. An electron is moving with a speed of ${10}^5\mathrm{m}/\mathrm{s}$ parallel to the conductor. The perpendicular distance between the electron and the conductor is $20\mathrm{c}\mathrm{m}$ at an instant. Calculate the magnitude of the force experienced by the electron at that instant.

 

Correct Option - 4


Detailed Solution:

$\mathrm{f}=\mathrm{e}\mathrm{v}\left(\frac{{\mu }_0\mathrm{i}}{2\pi \mathrm{r}}\right)$

$\mathrm{f}=\frac{1.6\times {10}^{-19}\times {10}^5\times 2\times {10}^{-7}\times 5}{0.2}$

$\mathrm{f}=8\times {10}^{-20}$ Newton

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