My self Abhishek , I am interested to join to pset University for BTech in computer science .How much kcet rank is required to get a free se
Asked about PES University - B.Tech. in Computer Science and Engineering
Second pu in progress I likely join to university for 2022
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1 Answer
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For general category students, the minimal cutoff for admission to PES University is 94746 to get a free se and also this is the best university which a good records of placements which can give you a better life style.
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For the students belonging to the General HS quota, the KCET last round closing rank for BTech in CSE was 83674. Candidates can refer to the table below to view the round-wise cutoff ranks:
| Round | KCET Last Round Closing Rank 2025 |
|---|---|
| 1 | 57600 |
| 2 | 74130 |
| 3 | 83674 |
If you belong to the General AI category, the BTech cutoff 2025 for the University of Mysore ranged between 73966 and 261014 in the last round. Candidates can refer to the table below to view the branch-wise last round closing ranks for KCET:
| Course | KCET Last Round Cutoff 2025 |
|---|---|
| B.Tech. in Artificial Intelligence and Data Science | 86897 |
| B.Tech. in Bio-Medical and Robotic Engineering | 261014.5 |
| B.Tech. in Computer Science and Design | 225014 |
| B.Tech. in Civil Environment Engineering | 232487 |
| B.Tech. in Artificial Intelligence and Machine Learning | 76921 |
| CSE | 73966 |
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