What is the procedure to take BTech admission at SRM TRP Engineering College?

0 24 Views | Posted 2 years ago
Asked by Nishar Ahmed

  • 2 Answers

  • D

    Answered by

    Debrata Sarkar | Contributor-Level 8

    a year ago

    1.TNEA Counseling: SRM TRP Engineering College uses the Tamil Nadu Engineering Admission (TNEA) counseling process to admit students to its engineering departments. To obtain a seat at the college, you must first register for TNEA and then go through the counseling process.
    2.TANCET: Another entrance alternative for SRM TRP Engineering College is the TANCET (Tamil Nadu Common Entrance Test). You can apply for TANCET and get a seat in college based on your ranking in the exam.

    3. Direct Admission: If you did not receive a seat through TNEA or TANCET, you may still apply for direct admission to SRM TRP Engineering College. However, the ava

    ...more
  • R

    Answered by

    Ritesh Kanojiya | Contributor-Level 10

    a year ago

    To apply for a BTech programme at SRM TRP Engineering College, perform the following actions:

    1. Verify eligibility: Candidates must have taken the Higher Secondary Examination (HSE) or a similar test in which three of the four topics studied under Part-III were physics, chemistry, and mathematics, or any examination in the 10+2+3 stream that included mathematics.

    2. Apply Online: Go to the admissions department of SRM TRP Engineering College's official website. Provide correct and comprehensive information when completing the online application form. Upload the necessary files as specified in the application.

    3. TNEA Counseling: Based on

    ...more

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Hi.

Basic Eligibility

 You must have passed Class 12 (10+2) from a recognised board with at least 50% aggregate marks. 

Mandatory subject requirement: You need Mathematics / Business Mathematics / Statistics / Allied Mathematics at 10+2 level as one of your subjects.

So if your commerce stream + computer Science in 12th included Mathematics or Business Mathematics or Statistics, then:

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