Can an M.Sc in applied mathematics student appear for NET exam?

0 1.7k Views | Posted 7 years ago
Asked by CHANDAN B V

  • 5 Answers

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  • Shiksha Ask & Answer

    Answered by

    Rakhi Agrawal | Contributor-Level 9

    6 years ago
    Yes, you can apply for the NET Exam under CSIR NET. CSIR NET is conducted only for the Science stream students which is conducted only in 5 subjects which are:
    Mathematical Science
    Life Science
    Chemical Science
    Physical Science
    Earth Science
  • Shiksha Ask & Answer

    Answered by

    Komal Sharma | Contributor-Level 8

    6 years ago
    Yes, you can apply for CSIR NET Exam.
  • Shiksha Ask & Answer

    Answered by

    Neha Garg | Contributor-Level 6

    6 years ago
    Yes, you can apply for CSIR NET Exam in mathematical Science. The Council of Scientific and Industrial Research conducts the CSIR NET for Mathematical Sciences exam. Except for the graduation or post graduation degree, you must fulfill the other criteria that you can check from here - https://scoop.eduncle.com/csir-net-eligibility-criteria
    For mathematical Science, CSIR Exam will be conducted in the evening session. If you scored good marks in the exam then you will get scholarships or awards, offered by CSIR.
  • Shiksha Ask & Answer

    Answered by

    Dr. Uma Sinha Principal | Scholar-Level 17

    6 years ago
    Hi,
    Candidates should have a minimum of 55% in their PG or an equivalent from any recognised university. Yes, you can appear for NET exam.
    Thanks!
  • A

    Answered by

    Aakash Saxena | Contributor-Level 7

    7 years ago
    Yes, you can apply for NET Exam, if you have completed the Post-graduation M.Sc or in running too. The NET Exam application forms is out and the last date to fill is 26th March 2018.
    To prepare for UGC NET Exam, you can take help from the given list of books.
    UGC NET/JRF/SET Teaching & Research Aptitude (General Paper I)
    By:
    Pratiyogita Darpan
    Publisher: Upkar Prakashan
    CSIR-UGC NET/JRF/SET Mathematical Science (Paper - I & II)
    By:
    Alok Kumar
    Publisher: Upkar
    UGC-CSIR JRF/NET Mathematical Sciences
    Publisher: G. K. Publications Pvt. Ltd
    CSIR-UGC-NET (Science) Paper I Guide
    By :
    Karan Deo
    Publisher: Ramesh Publishing House.

Similar Questions for you

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No. The authority has not released the UGC NET certificate for the December session 2025. The exam is scheduled to be conducted from December 31 to January 7, 2026. 

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The authority will release the UGC NET certificate on the official website at ugcnet.nta.nic.in and also on the e-certificate portal at ecertificate.nta.ac.in. Candidates can download it by using their login credentials including the application number and password or date of birth.

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  • Visit at ugcnet.nta.nic.in
  •  Click on the link available for the answer key
  • Use application number and password or the application number and date of birth to open the link
  • Enter the application number, password/date of birth, and security pin (as shown on the screen)
  • Click on Sign In and submit the Challenge Answer Key link
  • Select the correct answer option ID for the question ID for which the challenge needs to be made
  • Click on the 'Save Your Claims' button
  • Upload the supporting documents in a single PDF file to support your claim
  • Click on the 'Save Your Claims & Pay Fee' button
  • Pay INR 200 per question in the online mode
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The UGC NET answer key challenge fee per question is INR 200. It is non refundable whether the challenge is accepted or rejected. It can be paid online via debit card, credit card, net banking or UPI. Challenges made by the candidates will be verified by the panel of subject experts.

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Nitesh Pruthi

It is released by the National Testing Agency NTA a few days after the exam is conducted. The answer key helps candidates in calculating their probable scores and checking the accuracy of their responsesThe details provided on the UGC NET answer key are mentioned below:

  • Exam date
  • Exam shift
  • Exam subject name and code
  • Question ID
  • Correct option ID

 

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