Can I get a free seat with 22923 rank in TS EAMCET?
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1 Answer
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To be eligible for a free seat, candidates must score lower than 10,000 in the TS EAMCET 2024 exam. OU College of Technology, Vidya Jyothi Institute of Technology, Kakatiya Institute of Technology and Science, and more esteemed colleges rank between 15000 and 20000 in the TS EAMCET. Following the conclusion of the counselling sessions, TSCHE releases the TS EAMCET 2024 cutoff. To determine their prospects of being admitted to the college of their choosing, applicants can review the cutoffs from the previous few years. The cutoffs, which show the range of ranks within which any TS EAMCET member institute grants admissions, are made publ
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Candidates can access the TS EAMCET mock tests either from the official website which is free of cost or from third party edutech website, which provide the mock tests for a small amount.
The TS EAMCET mock test, provides candidates with an actual exam like feel. When students access the mock test, they can -
- Solve it online by referring to the questions and know the types of questions asked in the exam.
- There is a timer also just like the exam centre which helps students to keep track of the time.
- It helps students increase their question solving ability.
- It helps students increase their efficiency and speed of solving the questions.
- Mock tests are the best way to prepare for the TS EAMCET exam.
The TS EAMCET mock test is just like a practice session which can accessed via any third party edutech platform. It provides candidates with an actual exam-like feel. To ensure they prepare for the exam effectively.
To prepare for the TS EAMCET exam, candidates can refer to the NCERT books, however, they can also take help from supplementary books, but over burdening oneself with a lot of books is not recommended.
If candidates have focused well in their 10 and 10+2 classes, they can easily qualify in the exam. The question paper is similar to popular engineering entrance exams such as JEE Mains, but the difficulty level is of easy to moderate.
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