Can I get a seat in National Institute of Technology Karnataka? I got 147553 rank.

55 Views|Posted 7 years ago

Asked by Mohammed Rahif

5 Answers

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Answered by

Deepak Prajapati | Scholar-Level 16

6 years ago

Please go with this college predictor this will help you to choose best for you https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor Thank you

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Answered by

Sharath H Aithal | Scholar-Level 17

6 years ago

Hi, Visit this link to check colleges based upon your rank: https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor Good Luck. Hope it helps.

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Answered by

Yash Gupta | Scholar-Level 16

6 years ago

Hi Mohammed Rahif Kindly predict your college in this college predictor. JEE Main rank predictor is an online tool which predicts the candidates rank range and probable colleges based on the difficulty level of the examination, average marks scored in JEE Main and seats available in IITs, NITs, GFT

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Answered by

Mithun K G | Contributor-Level 8

7 years ago

Refer the link: https://www.shiksha.com/college/national-institute-of-technology-surathkal-mangalore-24187/admission#admission

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Answered by

Aishwarya Agrawal | Guide-Level 11

7 years ago

Hello there, you cannot get NIT, Surathkal with such a low rank. Also there are no any other method to get admission in such NIT. Try for other colleges.

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Yes, it is easy to apply for various courses at the National Institute of Technology Surathkal. Students just have to go to the institute's official website to apply. The admission is through many entrance tests for specific courses.

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National Institute of Technology or NIT Surathkal is in Karnataka and was established in 1960. It has 13 departments, 1 School, and 12 supporting centres. NIT Surathkal gives UG, PG and PhD courses in the areas of Engineering, Management, and Science.

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NIT Surathkal BTech cutoff 2025 was 3934 in round 1 for the General AI category, which later increased to 5316 in last round for the BTech ECE course. Students can refer to the table below to know the overall cutoff range for all other All India categories.

All India Category	JEE Main Cutoff Range 2025
General	3934 - 5316
OBC	1687 - 7933
SC	808 - 888
ST	459 - 459
EWS	599 - 6196

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Students who belong to the General AI category need to secure a rank between 1528 and 2158 to be eligible for BTech CSE branch. On the other hand, the OBC AI category students need a rank between 495 and 3690. Please note that other categories will have different cutoffs accordingly.