Can I get admission in Capital University for BTech with 60% in Class 12?

<p>Candidates need to meet both eligibility and selection requirements to apply for BTech course at Capital University. As per the eligibility criteria for BTech, candidates need to pass Class 12 with Physics, Chemistry and Mathematics with at least 55% aggregate (50% aggregate for SC/ ST). Hence, aspirants with 60% in Class 12 can apply for BTech programme. Aspirants who have qualified JEE Main or CUET will be preferred.</p>

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<p>Admission criteria for universities, including Capital University for B.Tech programs, are typically determined by various factors, and a percentage of 60% in Class 12th may or may not meet the specific requirements. Universities often consider a combination of academic performance, standardized test scores, and other relevant factors during the admission process.</p><p>To determine your eligibility, you should carefully review the admission guidelines provided by Capital University. Most universities have a minimum academic requirement, and it is essential to check if your 60% in Class 12th aligns with their specified criteria. Additionally, universities may have specific eligibility criteria for the B.Tech programs, such as acquiring a background in Science or mathematics.</p><p>If your Class 12th percentage falls below the university's specified threshold, it is advisable to explore other aspects of your academic profile. Some universities consider other factors, such as performance in entrance exams, extracurricular activities, and personal statements. Participation in relevant competitions or projects may also enhance your chances of admission.</p><p>To increase your chances, consider reaching out to the university's admission office for clarification on their specific requirements and inquiries about any alternative pathways or additional criteria that may be considered. Additionally, you may explore the option of improving your academic credentials through supplementary courses or exams to strengthen your application.&nbsp;</p><p>&nbsp;</p>

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