Can I get admission in this college with 90+ in CBSE 12th boards? What will be the fee structure then for B.Tech in CSE?
Asked about Sir M. Visvesvaraya Institute of Technology - B.E. in Computer Science and Engineering
Asked by Ricky Sahoo
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Yes, you can directly get the admission into B.Tech with 90% marks in 10+2, not only admission, you also stand to attain the highest scholarship of the phase in which you take admission.
It would be a good choice to opt for LPU as in the present scenario this is the university which caters to the all-round development of its students and nurtures it with care to boost the career to a pinnacle of ultimate success which might be the envy of many. The premier institution of LPU would come to me. LPU students are guided on niche technologies like Google, SAP and Oracle. Possessing such skill sets separates them from the ordinary and leads...more -
Depends on what your CET or ComedK rank is, not entirely on your board marks. There is a weightage given to your board marks only in the CET not ComedK. The fee structure also depends on if you are applying through CET or ComedK. The fee is higher if you are applying through ComedK. Right now, it is around Rs. 60,000 for students who join through CET and around Rs. 1,60,000 for those who join by writing ComedK.
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Per year, it is 1 lakh.
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Dear Ricky,
I have no idea about the fee structure of BTech in CSE at M. Visvesvaraya Institute of Technology. But being alumni of LPU, I would say that the fee is INR 190000 per semester. However, you may get a scholarship of 30% maximum at LPU in this programme.
There are a few points I would like to share about why CSE is good at LPU.
Good Placement: LPU has a good placement record for CSE students. Every year more than 500+ companies including national and multinational companies visit LPU for placement. A few of them are Microsoft, Amazon, Adobe, etc. in which they are placed. The maximum package availed for CSE is 42 lacs. per annum...more -
You can check the following link for more information - https://www.shiksha.com/college/sir-m-visvesvaraya-institute-of-technology-yelahanaka-bangalore-508
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Yes, you can directly get the admission into B.Tech with 90% marks in 10+2, not only admission, you also stand to attain the highest scholarship of the phase in which you take admission.
It would be a good choice to opt for LPU as in the present scenario this is the university which caters to the all-round development of its students and nurtures it with care to boost the career to a pinnacle of ultimate success which might be the envy of many. The premier institution of LPU would come to me. LPU students are guided on niche technologies like Google, SAP and Oracle. Possessing such skill sets separates them from the ordinary and leads t...more -
Yes the eligibility criteria for the programme is Pass with 60% aggregate marks in 10+2 (with Physics, Mathematics and English) or equivalent, subject to qualifying LPUNEST or In case student scored more than or equal to 90% in 10+2 , or 90 percentile in JEE Mains, then LPUNEST will be exempted and candidate may apply for admission.
LPU offers scholarship based on various categories like previous qualification percentages, LPU NEST exam, national level test, defense personnel or CAPF dependents and many more. Whichever will be the best applicable that will be reduced from the fees of every semester. The fees structure depends upon th...more -
Bravo for the great score. Definitely you can get admission in B.Tech CSE. You need to qualify the LPU NEST Entrance test and there after you will be eligible to seek admission in LPU. Well to clear your point of doubt, let me explain, in LPU if you are applying for admissions in B.Tech CSE, the following scholarship will be applied for JEE mains qualifier
If JEE score is >=95 percentile scholarship is 30%
If JEE score is in between 90 - 95 percentile scholarship is 25%
If JEE score is in between 85 - 90 percentile scholarship is 20%
The process of qualifying the criterion of admission you have to qualify LPU NEST and the eligibility f...more
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