Can I get B.Des. in Fashion Design with a NIFT rank of 1299 at NIFT Bhubaneswar?

0 7 Views | Posted a month ago
Asked by Shiksha User

  • 2 Answers

  • P

    Answered by

    PRINCE MISHRA | Contributor-Level 7

    a month ago

    Yes, a NIFT rank of 1299 is likely to get you into the B.Des. in Fashion Design programme at NIFT Bhubaneswar, as the cutoff for the General category was between 1250-1394 in recent years.

  • R

    Answered by

    Rashmi Sinha | Contributor-Level 10

    a month ago

    In 2025, the NIFT cutoff ranks ranged between 1250 and 1448 for the students belonging to the General AI quota. So, yes, if you belong to the General AI category, there is a chance that you can secure a seat at the National Institute of Fashion Technology, Bhubaneswar, for a B.Des in Fashion Design course. To view the round-wise cutoff ranks for the General category students, refer to the table below:

    RoundNIFT Closing Rank 2025 for B.Des in Fashion Design
    11250
    21394
    31448

Similar Questions for you

R
Rashmi Sinha

The NIFT Bhubaneswar cutoff 2025 has been released up to multiple rounds, wherein the closing rank for B.Des. in Textile Design during Round 3 admission was 8741 for the students belonging to the General AI quota. For other categories, check out the table provided below:

CategoryNIFT Round 3 Cutoff 2025 
General8741
OBC5063
SC8741
EWS7155
R
Rashmi Sinha

NIFT Bhubaneswar cutoff 2025 has been released for different categories of students belonging to the AI quota. For the General AI quota, the NIFT Round 1 closing ranks varied between 306 and 2090, wherein the toughest course to get admission to was Master of Fashion Management (MFM) with the lowest cutoff rank. Please note, the lower the cutoff rank, the higher the competition and vice versa. For other courses, the cutoff details for the General AI category students are tabulated below:

CourseNIFT Round 1 Cutoff 2025 (General AI quota)
B.Des. in Accessory Design1282
B.Des. in Fashion Communication933
B.Des. in Fashion Design1250
B.Des. in Textile Design2090
B.FTech. in Apparel Production777
Master of Fashion Management (MFM)306
N
Nitesh Lama

NIFT Bhubaneswar accepts NIFT scores for admission to UG and PG programs. The NIFT Bhubaneswar cutoff 2025 was released for different categories belonging to the All India quota. The cutoff for the General AI category candidates was closed between the range of 306 and 2090. Therefore, the highest cutoff rank for admission among the General AI category was 2090, which was admission to B.Des. in Textile Design. On the other hand, the lowest cutoff stood at 306 for Master of Fashion Management (MFM). So, candidates having a rank of 350 can fetch any course except MFM in 2025.

A
Annu navariya

To get direct admission in the Diploma in Mechanical Engineering (Automobile) at Government Polytechnic College Lucknow through the Uttar Pradesh Board of Technical Education (BTEUP), one generally needs to pass through the Joint Entrance Examination Council Uttar Pradesh (JEECUP), although direct admissions based purely on Class 10th marks require a good academic background. Typically it requires a minimum of 35% marks in class 10th with Mathematics and Science as compulsory subjects; higher marks increase the probabilities, especially in sought after branches like Mechanical Engineering. Details of the eligibility criteria have to be

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N
Nishtha Shukla

Apart from qualifying the entrance exam, aspirants also need to fulfil the set eligibility requirements. The basic eligibility is Class 12 for UG courses and graduation for PG programmes. Below is course-wise eligibility for NIFT Bhubaneswar:

Course Name

Common Eligibility

BDes

Class 12 examination from any recognised Central/ State Board of Secondary Examination, such as Central Board of Secondary Education/ State Board New Delhi/ Council for Indian School of Certificate Examination

BFTech

Class 12 examination or from any recognised Central/ State Board of Secondary Examination, such as Central Board of Secondary Education/ State Board New Delhi/ Council for Indian School of Certificate Examination with Physics and Mathematics

MFM

Undergraduate degree in any discipline from any institute/ university recognised by law in India
or
UG Diploma of minimum three-years duration from NIFT/ NID

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