Students are admitted to the College of Engineering and Technology, Bhubaneswar (CET Bhubaneswar) on the basis of several factors, such as their JEE Main score, the college's cutoff, and the availability of seats. Although scoring 70% on the JEE Main is an impressive feat, acceptance to CET BBSR cou
Upvote 
The College of Engineering and Technology, Bhubaneswar (CET Bhubaneswar) admits students based on a number of criteria, including JEE Main score, college-set cutoff, and available seats. While receiving a 70% on the JEE Main is a commendable accomplishment, admission to CET BBSR may be competitive d
Upvote If your JEE Main percentile score is around 70%, your rank would be between 2,50,000 and 3,00,000. This rank may not be sufficient to secure a seat in the top NITs or IIITs, but you can still consider applying to reputed private engineering colleges that accept a percentile score within this range.
F
Upvote Similar Questions for you
NIT Trichy JEE Main cutoff 2025 for the SC All India category varied from 43 to 119057 for the BArch and all BTech course specialisations. Overall the BArch course had the lowest last and first round cutoff at 43. In the case of BTech course branches, the hardest course in the last round was BTech E
Students who belong to the General AI category need to secure a rank between 1528 and 2158 to be eligible for BTech CSE branch. On the other hand, the OBC AI category students need a rank between 495 and 3690. Please note that other categories will have different cutoffs accordingly.
The BTech CSE last round rank for the General AI category in 2025 was 4245. In 2024 and 2023, the cutoff in the last round was 3365 and 4218, respectively. This difference in the ranks suggests the cutoff trend has been fluctuating over the years. Please note that other categories will have differen
To get admission at NIT Rourkela, General AI category students need to attain a rank of 85536 or below to be eligible, according to the last round NIT Rourkela JEE Main cutoff 2025.
For the students who belong to the General HS category, the required rank needed for admission was at least 12735
NIT Rourkela JEE Mains cutoff 2025 concluded with the release of the final round cutoff. For the General AI category, the BTech CSE overall cutoff ranged from 3122 to 4245. On the other hand, for the General HS category, the overall cutoff varied between 7371 and 7853. Students should know that the
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Didn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering