Hi, I am a 12th qualified student. I want to know the cut off for BE electronics and telecommunication?

For 2018 admissions, it was around 95-100 MHT CET exam.

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The eligibility criteria for BE electronics and telecommunication engineering is as follows: Candidate should be an Indian National Should have passed the Higher Secondary Certificate HSC (standard. XII) examination of the Maharashtra State Board of Secondary and Higher Secondary Education or its equivalent examination with subjects English, Physics and Mathematics as compulsory subjects along with one of the Chemistry or Bio-Technology or Biology or Technical or Vocational subjects and obtained at least 50% marks (at least 45% marks, in case of Backward class categories and persons with disability candidates belonging to Maharashtra State only) in the above subjects taken together; and should obtain non zero positive score in JEE Main Paper I or the candidate should have appeared in all the subjects in CET and should obtain a non zero scores in CET conducted by the Competent Authority. However, preference shall be given to the candidate obtaining a non-zero score in JEE Main Paper I over the candidates who obtained a non-zero score in CET. Or Passed Diploma in Engineering and Technology and obtained at last 50% marks (at least 45% marks, in case of Backward class categories and persons with disability candidates belonging to Maharashtra State only). Visit this link for more details: <a href="https://www.google.com/url?sa=t&source=web&rct=j&url=https://www.shiksha.com/college/amp/sides-graduate-school-of-technology-nerul-Mumbai-24781&ved=2ahUKEwiwj9iTmZHiAhVMpI8KHbGtB9EQFjAjegQIARAB&usg=AOvVaw07LqiF4jWn-rZOSMRi-vjq&ampcf=1&cshid=1557499479324" style='word-wrap:break-word;'>https://www.google.com/url?sa=t&source=web&rct=j&url=https://www.shiksha.com/college/amp/sides-graduate-school-of-technology-nerul-Mumbai-24781&ved=2ahUKEwiwj9iTmZHiAhVMpI8KHbGtB9EQFjAjegQIARAB&usg=AOvVaw07LqiF4jWn-rZOSMRi-vjq&ampcf=1&cshid=1557499479324</a> hope it helps thank you.

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