hi i jitendra garg my jee main 2019 percentile is 96.67 and rank is 37760 can i get cse in lnmiit

NIT Trichy JEE Main cutoff 2025 for the SC All India category varied from 43 to 119057 for the BArch and all BTech course specialisations. Overall the BArch course had the lowest last and first round cutoff at 43. In the case of BTech course branches, the hardest course in the last round was BTech E

Students who belong to the General AI category need to secure a rank between 1528 and 2158 to be eligible for BTech CSE branch. On the other hand, the OBC AI category students need a rank between 495 and 3690. Please note that other categories will have different cutoffs accordingly. 

The BTech CSE last round rank for the General AI category in 2025 was 4245. In 2024 and 2023, the cutoff in the last round was 3365 and 4218, respectively. This difference in the ranks suggests the cutoff trend has been fluctuating over the years. Please note that other categories will have differen

To get admission at NIT Rourkela, General AI category students need to attain a rank of 85536 or below to be eligible, according to the last round NIT Rourkela JEE Main cutoff 2025. 

For the students who belong to the General HS category, the required rank needed for admission was at least 12735

NIT Rourkela JEE Mains cutoff 2025 concluded with the release of the final round cutoff. For the General AI category, the BTech CSE overall cutoff ranged from 3122 to 4245. On the other hand, for the General HS category, the overall cutoff varied between 7371 and 7853. Students should know that the