How can I calculate my score using JEE Main answer key?
To calculate the score using JEE Main keys, add 4 marks for a correct answer and deduct 1 marks for a wrong attempt.
You can go find the marks from the answer key and response sheet. If one answer is correct, it's four marks. For an incorrect one, one mark is reduced. Then you can sum all.
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Indus university CSE cutoff 2024 for the General HS category was 50604 in the last round. Hence, students need to attain a rank of at least 50604 to be considered eligible for admission. Check the list below to know the Indus university category-wise cutoff 2024 for the last round.&nb
No. Admission to B.E./B.Tech programmes in Tamil Nadu goes through TNEA, which uses your Class 12 marks. There is no separate entrance test for most colleges. Your board marks decide your rank. So focus on your Class 12 scores. Register on the TNEA portal as soon as it opens.
The JEE Main cutoff 2026 for BTech in CSE at Jaypee Institute of Information Technology is 80910. Students looking for JIIT Noida admissions in BTech CSE branch need to secure the required marks.
Yes, you can get direct admission at Noida Institute of Engineering and Technology (NIET), Greater Noida, without a JEE Main score via management quota. Please note that the management quota fees are way higher than the regular fees.
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