How many mark in JEE Mains 2019 we have to secure to get a seat in NIT, Rourkela for B.Tech in computer science and engineering?

427 Views|Posted 7 years ago

Asked by Kishan Behera

6 Answers

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Srinarayan Prajapati | Guide-Level 15

6 years ago

Hello Please go with this college predictor this will help you to choose best for you https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor Thank you.

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Answered by

Jyoti Prajapati | Scholar-Level 16

6 years ago

Please visit this college predictor: https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor

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Answered by

Yash Gupta | Scholar-Level 16

6 years ago

Hi Chinnu Rao, Kindly predict your colleges in this college predictor. JEE Mains rank predictor is an online tool which predicts the candidates rank range and probable colleges based on the difficulty level of the examination, average marks scored in JEE Main and seats available in IITs, NITs, GFTI

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Answered by

Swayamprava Nayak | Contributor-Level 8

7 years ago

Hi, Placements are really good at NIT-R. Average salary for computer Science branch is around INR. 7 lacs - INR. 8 lacs per annum. The highest package offered is lacs 39 lacs p. a. the lowest is lacs 3 lacs p. a. not only technical but management related jobs are also offered at NIT-r. 30 percent

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Answered by

Simran Kaur | Beginner-Level 4

7 years ago

Well, every year, the rank changes and the marks for each institute changes. Definitely, you have to score more than 170 marks and yes, category can play a big role in getting admission specially if its a CSE branch. All the best.

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Answered by

Pradeep Kumar | Scholar-Level 18

7 years ago

Hi, the opening and closing ranks in B.Tech CSE for NIT, Rourkela for year 2018 is 4209 and 8524 respectively. Hence you have to score more than 150.

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