How many marks are required for to take the admission in this CIT clg..?

Asked about Chennai Institute of Technology - B.E. in Computer Science and Engineering

0 115 Views | Posted 5 years ago
Asked by Ajit Patil

  • 2 Answers

  • Engineering admission in Tamil Nadu is based on cutoff mark calculated for mathematics, physics and chemistry using this formula (maths +physics/2 + chemistry / 2 i.e. M 100+P 100/2 + C 100/2 = 200 max cutoff ). In TNEA Counseling, Chennai Institute of Technology previous year's average cutoff for general Category was 185 ( approximately above 90% in MPC) for BC Category 175 ( above 85% in MPC ) for other categories less 10 cutoff from previous category.
  • D

    Answered by

    Dhanalakshmi Baskaran

    5 years ago
    The minimum eligibility of getting admission in CIT college is getting 50% for General, 45% for Backward and 40% for other Reserved category aggregate marks in Physics, Chemistry and Mathematics in XII exam.

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