How many marks are required to get admission in computer science at KIIT University?
Asked by Abhishek kumar
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The JEE Mains exam was conducted in the month of April and the results have been announced recently. Well, the JEE cut-off depends on the exam level as well as the number of students appears in the exam every year. This year, the cut-off is likely to be increased.
General-74 marks
OBC 45 Marks
SC-29 marks
ST- 24 marks -
Hi, for applying to B.Tech (4 years) course you should fulfill the following criteria:-
Candidates who have passed 10+2 examination in 2016, 2017 or appearing in 10+2 examination in 2018 are only eligible to apply for B.Tech.
Should have studied in regular full-time formal education in their schooling/college. Pass in 10 +2 or its equivalent with at least 60% marks in Physics, Chemistry and Mathematics taken together. B.Tech & M.Tech. (Dual Degree) biotechnology. Pass in 10+2 or equivalent with at least 60% marks in Physics, Chemistry and Mathematics/Biology taken together.
Should have born on or after July 1, 1997. -
You need to get a very good rank (above 4000). Closing rank for CSE at KIIT in 2015 was 5044. So, for 2018, maybe it will be around 4800 or above. So, prepare well. Sometimes, it drops and sometimes it increases. It depends on the number of applications and seats available. But a rank of 4000 and above will be good.
Good luck.
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