How much is 120 marks in JEE Mains percentile?
The National Testing Agency (NTA) will declare the JEE Mains result 2026 in the form of percentile scores. Candidates can check here the previous year JEE Main marks vs percentile data to understand how much is 120 marks in JEE Main percentile.
As per the last year JEE Main marks vs percentile analys
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Scoring 120 marks in JEE Main 2026 generally corresponds to a percentile range of 95 to 97.5+ and an AIR of roughly 35,000 to 60,000. This is as per previous year trends and expert analysis.
Upvote 120 marks in JEE Mains generally corresponds to a percentile between 95 and 97+ (approx. 30,000 to 60,000 rank).
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120 marks in JEE Main correspond to the following percentiles across categories:
- General Category: ~92-96 percentile
- OBC-NCL/EWS: ~90-95 percentile; qualifying cutoff is lower for these categories
- SC/ST: ~70-80 percentile (Qualifying cut-off is much lower as compared to General)
The cutoff ranges
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The I2IT Pune JEE Main cutoff 2025 was released in the form of ranks for the All India categories. For the General AI category, the BE in the Computer Engineering branch had the overall cutoff ranging from 42136 in the first round to 52834 in the last round. Hence, General AI students needed to
The selection process for the All India quota students is based on their JEE Main ranks. Students who want admission to I2IT Pune need to appear in the CAP counselling process to avail a seat for any BE course.
The minimum rank required for admission was 68635 for the General AI category. Hence
The minimum rank required to get admission at I2IT Pune would depend on the category you belong to. The I2IT Pune JEE Main cutoff 2025 for the General AI category says that a rank of at least 61370 is required to be eligible for admission to the BTech in Information Technology department. This
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