How much rank in JEE Advanced is required for IIT Delhi?
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2 Answers
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The IIT Delhi cutoff 2024 has been concluded for admission to the BTech and Integrated BTech courses. As per the JEE Advanced 2024 cutoff for the Last Round, the closing rank for BTech ranged between 116 and 4849 for the General AI category students. The toughest course to get into IIT Delhi was CSE. So, candidates seeking admission at this institute must aim to secure up to 4850 rank to be eligible for BTech admission. The required cutoff ranks will vary based on the categories you fall into. To get an idea of the category-wise JEE Advanced cutoff range for BTech admission at IIT Delhi, refer to the table below:
Category JEE Advanced Round 1 JEE Advanced Last Round General 116 - 4754 116 - 4849 OBC 89 - 3068 89 - 2749 SC 48 - 1765 50 - 1780 ST 23 - 991 23- 991 EWS 33 - 1139 35 - 1215 PWD 5 - 159 5 - 159
Similar Questions for you
To be eligible for JEE Advanced JoSAA counselling:
- Candidates should have JEE Advanced rank
- Candidates must have passed class 12 or equivalent exam
- Candidates should have studied Physics, Chemistry and Maths in class 12
- In class 12, canmdidates must have score 75% aggregate marks or must be in top 20 percentile scorers in class 12 of their respective school board.
No, your candidature will be rejected as you need to have minimum of 75% in class 12 to be eligible for admisison to the IITs, NIT, IIITs and GFTIs via the JoSAA counselling. Even if you pass JEE Advanced and JEE Main, of you do not have 75% minimum marks in class 12 boards you will no get admissions.
Devdutta Majhi was the female topper in JEE Advanced 2025. She has scored 312 marks out of 360 marks and got anm all India rank of 16.
In 2025, the number of male candidates who passed JEE Advanced were 44,974 and 9,404 females qualified.
1,87,223 candidates registered for JEE Advanced 2025 and 1,80,422 appeared in the exam. Of them, 54,378 passed the JEE Advanced exam in 2025.
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