How much rank should I score to get IIT Roorkee?
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2 Answers
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IT JAM Fifth Admission List 2024 has been released for IIT Roorkee admisison to the MSc courses. As per the IIT Roorkee JAM cutoff 2024, the required score to get into IIT Roorkee for General All India category candidates varied between 52 and 232. Similarly, for the OBC AI category candidates, the required rank lie between 109 and 420.
So, considering the previous year rank, one can easily get a call from IIT Roorkee with a JAM score of 232 under General AI category. Meanwhile, candidates can refer to the table below to check out the IIT Roorkee MSc cutoff 2024 for Round 1:
Course 2024 M.Sc. in Physics 232 M.Sc. in Chemistry 221 M.Sc. in Applied Geology 52 M.Sc. in Mathematics 215 M.Sc. in Economics 64 -
IIT JAM First Admission List has been released on Jun 1 on the official website of IIT JAM 2023 at jam.iitg.ac.in. The last date for online payment of fee booking fee for JAM First Admission List 2023 is Jun 7. IIT JAM 2023 is to be conducted in four rounds for admission to MSc course. IIT Guwahati is the coordinating institute for JAM 2023. IIT JAM Second Admission List is scheduled to release on Jun 15 and the last date for online payment of seat booking fee for the same will be Jun 21. Further Third and Fourth Admission Lists are scheduled for release on Jun 26 and Jul 7, respectively. The last date for online payment of seat bookin
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Similar Questions for you
For students belonging to the General AI quota, most of the BTech branches remained open till the last round for admission at IIT Roorkee. The cutoffs of different branches vary across rounds and categories. Some of the BTech branches, such as CSE, ECE, Civil, and Mechanical, etc., reflected a rise in the last round, closing ranks as compared to initial rounds, indicating IIT Roorkee seats remained vacant till the last round for BTech admission. Whether the branch will remain open till the last round or not depends on the availability of seats allocated for each category. In the meantime, candidates can check out the round-wise cutoff
To get into IIT Roorkee, students must target to secure a maximum rank of up to 2556 for BTech admission if they belong to the General AI quota. The lower the cutoff rank, the higher the probability of getting the top BTech branch for admission. The required cutoff rank varies for different rounds, courses, specialisations and categories. Candidates can refer to the table below to view the IIT Roorkee branch-wise required cutoff in the last round for SC AI category students.
| Course | JEE Advanced Cutoff 2025 (SC AI Quota) |
|---|---|
| B.Tech. in Computer Science and Engineering | 129 |
| B.Tech. in Data Science and Artificial Intelligence | 213 |
| B.Tech. in Electronics and Communication Engineering | 394 |
| B.Sc. + M.Sc. in Mathematics and Computing | 569 |
| B.Tech. in Electrical Engineering | 572 |
| B.Tech. in Mechanical Engineering | 1039 |
| B.Tech. in Chemical Engineering | 1333 |
| B.Tech. in Energy Engineering | 1470 |
| B.Tech. in Engineering Physics | 1540 |
| B.Tech. in Civil Engineering | 1655 |
| B.Tech. in Production and Industrial Engineering | 1717 |
| B.Tech. in Metallurgical and Materials Engineering | 2026 |
| Integrated B.Sc. + M.Sc. in Economics | 2176 |
| B.Tech. Biosciences and Bioengineering | 2210 |
| Integrated B.Sc. + M.Sc. in Physics | 2240 |
| B.Sc. + M.Sc. in Chemical Sciences | 2318 |
| Integrated M.Tech. in Geophysical Technology | 2486 |
| Integrated M.Tech. in Geological Technology | 2556 |
| Bachelor of Architecture (B.Arch.) | 3181 |
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