How much should I score in JEE paper 2 (2018) to get admission for B.Arch in NIT-Calicut? I am from OBC category.

If you belong to the OBC category and want to secure a seat at NIT Calicut for the M.Tech course, you must aim to target a cutoff score of up to 694 or higher to get admission during the Round 1 cutoff list. Considering the competitive scores, the top three M.Tech specialisations for Round 1 admission were Computer Science and Engineering (694) and Computer Science and Engineering (Information Security) (671) for the OBC category students. 

To view the required cutoff scores for different specialisation during the Round 1 admission, refer to the table below:

For students belonging to the General AI quota, the GATE CCMT Round 1 cutoff scores varied between 351 and 731. For top M.Tech branches like CSE and CSE (Information Security), the cutoff scores stood at 731 and 694, respectively. Considering the first round cutoff 2025, other top M.Tech specialisations were Microelectronics and VLSI Design with a cutoff score of 647 and Electronics Design and Technology (600). For the OBC category students, the first-round cutoff scores for CSE and CSE (IS) stood at 694 and 671, respectively, under the All India quota. 

If you belong to the General AI category, the NIT Calicut JEE Main cutoff 2025 for Round 1 varied between 4678 and 28830 for admission to the BTech course across multiple specialisations. The one with the lowest cutoff rank of 4678 was Computer Science and Engineering. For the OBC category candidates, the JEE Main cutoff ranks were between 1529 and 10104. Candidates can refer to the table below to view the Round 1 cutoff range for different categories for admission to the BTech course: