How much weightage the Class 11 Math Chapter 2 Relations and Functions in class 11 annual exams?

0 3 Views | Posted 6 months ago
Asked by Piyush Vimal

  • 1 Answer

  • E

    Answered by

    Esha Garg

    6 months ago

    Chapter 2 Relations and Functions of Class 11 Maths holds moderate weight in the annual exams, usually carrying around 6 to 8 marks out of the total 80 in the theory paper. 

    Class 11 Maths Relations and Functions plays an important role in both in Class 11 and later in Class 12, to understand advance concepts required for competitive exams . Students will get a mix of short answer questions like basic definitions or finding domains and ranges as well as slightly more detailed questions that test your grasp of different types of relations and functions in class 11 annual exams.

Similar Questions for you

A
alok kumar singh

Reflexive :for (a, b) R (a, b)

-> ab– ab = 0 is divisible by 5.

So (a, b) R (a, b) " a, b Î Z

R is reflexive

Symmetric:

For (a, b) R (c, d)

If ad – bc is divisible by 5.

Then bc – ad is also divisible by 5.

-> (c, d) R (a, b) "a, b, c, dÎZ

R is symmetric

Transitive:

If (a, b) R (c, d) ->ad –bc divisible by 5 and (c, d) R (e, f) Þcf – de divisible by 5

ad – bc = 5k1               k1 and k2 are integers

cf– de = 5k2

afd – bcf = 5k1f

bcf – bde = 5k2b

afd – bde = 5 (k1f + k2b)

d (af– be) = 5 (k1f + k2b)

-> af – be is not divisible by 5 for every a, b,

...more
V
Vishal Baghel

x = n = 0 c o s 2 n θ = c o s 0 θ + c o s 2 θ + c o s 4 θ + . . . . . = 1 + c o s 2 θ + c o s 4 θ + . . . . .

a = 1, r = cos2

x = S = a 1 r = 1 1 c o s 2 θ = 1 s i n 2 θ

Similarly, y = 1 c o s 2 θ 1 y = c o s 2 θ

z = x y x y 1 x y z z = x y . . . . . . . . . . . ( i )

Also, 1 x + 1 y = 1 x + y = x y . . . . . . . . . . ( i i )

(i) & (ii) xyz = xy + z (x + y) z = xy + z

V
Vishal Baghel

Total number of possible relation = 2 n 2 = 2 4 = 1 6

Favourable relations = ? , { ( x , x ) } , { ( y , y ) }

{ ( x , x ) , ( y , y ) }

{ ( x , x ) , ( y , y ) , ( x , y ) , ( y , x ) }

Probability = 5 1 6

V
Vishal Baghel

A = {1, 2, 3, 4}. As (4, 4)  R so not reflexive

Also not transitive

V
Vishal Baghel

3 2 x 2 1 x 0 p u t 2 x = t

3 t 2 t 0 t 2 3 t + 2 0

( t 1 ) ( t 2 ) 0 t [ 1 , 2 ]

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