How to get into A.R.J College of Engineering and Technology (ARJCET) for UG/PG courses? What's the eligibility for admission?
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2 Answers
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Candidates who intend to get into A.R.J College of Engineering and Technology, ARJCET for UG courses, are required to pass 10+2 education in a recognised board with at least 50 percent marks in aggregate in Physics, Chemistry, and Mathematics. Along with this, they must have qualified in entrance exams like JEE Main and Tamil Nadu Engineering Admissions or TNEA. Candidates will have to be possessing B.Tech or equivalent degree in the relevant stream along with an aggregate score of minimum marks and a valid GATE score or the college's entrance exam for PG courses. Admission is via entrance examination scores and counseling process resp
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Qualified eligibility and application process should be followed by the candidates for admission into A.R.J College of Engineering and Technology for UG/PG courses.
Eligibility:
- Undergraduate Courses (B.E./B.Tech): A student should have completed 10+2 or equivalent with Physics, Chemistry, and Mathematics as compulsory subjects for the UG course. Admissions normally take place through Tamil Nadu Engineering Admissions (TNEA) or through management quota.
- Postgraduate Courses (M.E./MBA): Students possessing a graduation degree in the relevant stream would be requiring the qualifying score as defined by the institution.
Similar Questions for you
The results for the semester exams at A.R.J College of Engineering and Technology (ARJCET) are usually released within a few weeks from the date of completion of the exams. The exact date differs with each semester, and it is communicated through official notices or college website.
Usually, the TNEA results for A.R.J College of Engineering and Technology are declared by the Directorate of Technical Education, Tamil Nadu. Generally, the TNEA results are out in June or July following the commencement of counseling process. The date for declaration of TNEA, however, may vary each year.
Candidates who wish to apply for B.E. / B.Tech at A.R.J College of Engineering and Technology (ARJCET) need to register first on the Tamil Nadu Engineering Admissions (TNEA) portal. After registration, fill up the online application form with personal, academic, and contact details. Upload necessary documents such as 10th and 12th marksheets, community certificate if applicable, and photographs. Pay the required application fee online. Once the form is submitted, candidates get considered for counseling process through which seats will be assigned based on the TNEA cutoff. After seat allotment, candidates will have to do document verif
The cutoff ranks for the Tamil Nadu Engineering Admissions (TNEA) for the A.R.J College of Engineering and Technology (ARJCET) in the year 2024 are different for various courses and categories. For the Open Category, the cutoff ranks are given below:
BE Electronics & Communication Engineering: 57,427 in Round 2, 192,791 in Round 3.
BE Computer Science and Engineering: 69,970 in Round 2, 195,202 in Round 3.
B.Tech Artificial Intelligence and Data Science: 101,248 in Round 2, 173,455 in Round 3.
BE Agricultural Engineering: 120,667 in Round 2.
BE Electrical and Electronics Engineering: 164,690 in Round 2.
BE Mechanical Engineering: 178,143
The following are the procedures for admission to A.R.J. College of Engineering and Technology (ARJCET):
According to TNEA (Tamil Nadu Engineering Admissions), applicants may use their Class 12 grades and the TNEA merit list if they finished Physics, Chemistry, and Mathematics in their 12th grade year.
Management Quota: Candidates who meet the minimum requirements for admission but fall short of the TNEA ranking criteria may apply for direct admission through the management quota.
Lateral Entry: Applicants with diplomas may be admitted directly to the second year of B.E. or B.Tech programs.
For additional information about dates and update
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