I have got 63% in 12th and 50% in my BCA. Am I eligible for NIMCET exam?

Hello dear, I am sharing you the link which will give you all basic idea of the exams from the eligibility, syllabus, exam date and other sorts of information. This will help you to clear all the doubts regarding your upcoming exams: <a href="https://www.google.co.in/url?sa=t&source=web&rct=j&url=https://www.shiksha.com/university/national-institute-of-technology-durgapur/exams/amp/nimcet&ved=2ahUKEwi0wqPZ-qPbAhXMeisKHWNIBA4QFjABegQIBxAB&usg=AOvVaw0GFjLYbVUhmpEMJbG-FsR_&cf=1" style='word-wrap:break-word;'>https://www.google.co.in/url?sa=t&source=web&rct=j&url=https://www.shiksha.com/university/national-institute-of-technology-durgapur/exams/amp/nimcet&ved=2ahUKEwi0wqPZ-qPbAhXMeisKHWNIBA4QFjABegQIBxAB&usg=AOvVaw0GFjLYbVUhmpEMJbG-FsR_&cf=1</a> All the best.

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment

NIMCET 2018 Eligibility Candidates must be an Indian citizen Candidates must have secured least 60% marks in aggregate or 6.5 CGPA on a 10 point scales (55% marks or 6.0 CGPA on a 10 point scale in case of SC/ ST) in (I) B.Sc. / B.Sc. (Hons) / BCA / BIT of minimum three years full-time with Mathematics/ Statistics/Equivalent subject *as one of the subject from a recognised University. Students with BE/B Tech or equivalent from a recognised University can take the exam. Aspirants who will be appearing for the qualifying examination can also apply for NIMCET-2018. However, such aspirants need to furnish the proof (in the form of a certificate issued by the Head of institution where the candidate has studied) of candidature for writing the exam during the academic year 2017-18. The proof needs to be submitted during the counseling process. Aspirants who have completed or completing degree three year B.Sc. / B.Sc. (Hons)/BCA/ BIT from Open Universities can also apply provided their programme is approved by UGC / AICTE and Distance Education Council (DEC) of Government Of India. Note: Conversion of scored marks from CGPA to percentage and vice-versa is not allowed.

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment