I have scored less than the cut-off marks (74) in JEE Mains. Can I apply for B.Tech?

Marksheet and Adhaar details must be matched. So you have to approach to 10th passing school with relevant documents. The school will submit the application to CBSE regional office for correction.

The sum of a magnetic field that passes through a given surface area is called the magnetic flux. The mathematic formula is? = BA cos (? ). 

This chapter covers the concepts of potential, capacitors, and potential energy. It is considered as one of the easy chapter of the class 12 Physics.

It talks about the atom. According to the Greek philosophers earlier, the atoms were the smallest part of matter that cannot be further divisible. Later, Dalton's atomic theory suggested that atom is the ultimate particle of matter. This theory was challenged later on by experiments done towards the end of the 19th and beginning of the 20th century. These experiments found that atoms are made up of electrons, protons and neutrons.

Honestly, going for CSE at Chandigarh University with your score sounds like a solid choice. I'm saying this because CU has become a hub for tech placements and internships, and the environment is pretty competitive in a good way. Your 88 percentile in JEE Main could also land you a scholarship, which is a big plus—you might save up to 50% on your semester fees depending on your exact AIR.

From what students share, CU has modern labs, coding clubs, hackathons, and even international exposure programs. That kind of ecosystem really helps if you're serious about building a career in CSE.