I've got 98.3295 percentile in JEE Mains & am from Bihar and OBC category. Will I be able to get admission?

Asked about NIT Durgapur - National Institute of Technology - B.Tech. in Computer Science and Engineering

I've got 98.3295 percentile in JEE Mains and have 86.2% in 10+2 CBSE.

0 68 Views | Posted 5 years ago
Asked by Akhilesh Kumar

  • 2 Answers

  • Shiksha Ask & Answer

    Answered by

    pradeep kumar Sr. Section Engr(Design) | Scholar-Level 18

    5 years ago
    The last year opening and closing ranks in B.Tech CSE in OBC(NCL) for Neutral gender under home state quota were 3004 and 19569 respectively up to 7th rounds. While in two special rounds there were 118571 and 136996 respectively.
    On the basis of your JEE-Main percentile your predicted rank is about 14609, Hence yours chances are very high.
    Good Luck
  • Shiksha Ask & Answer

    Answered by

    Yash Gupta | Scholar-Level 16

    5 years ago
    Hi,
    Kindly predict your college in this college predictor. JEE Mains rank predictor is an online tool which predicts the candidates rank range and probable colleges based on the difficulty level of the examination, average marks scored in JEE Mains and seats available in IITs, NITs, GFTIs, and other SFTIs. The rank predicted might not be accurate but it certainly does give an idea to the aspirant. Know your college admission chances based on your JEE Main Rank, Home State, Caste, Gender, etc. here:
    https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor

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