I want to know about the latest cutoff information for B.Tech.-M.Tech. in Computer Science & Engineering (Cyber Security) at NFSU.

<p>The latest cutoff information for B.Tech.-M.Tech. in Computer Science &amp; Engineering (Cyber Security) at NFSU (National Forensic Sciences University) is as follows:</p><p>The cutoff scores for B.Tech.-M.Tech. in Computer Science &amp; Engineering (Cyber Security) at NFSU range from 17.75 to 65.5 for the General category students . The cutoff scores vary for different categories, such as EWS, OBC-NCL, SC, ST, etc., with the lowest cutoff being 13 for OBC-NCL and the highest being 56.25 for the General category . The admission process for B.Tech.-M.Tech. in Computer Science &amp; Engineering (Cyber Security) at NFSU involves filling 50% of the seats through JEE (Mains) scores and the remaining 50% based on the National Forensic Admission Test (NFAT) 2025 . These cutoff scores provide an overview of the competitive scores required for admission to the B.Tech.-M.Tech. program in Computer Science &amp; Engineering (Cyber Security) at NFSU.</p>

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<p>To know the exact cutoff required to get admissions into BTech-MTech in Computer Science &amp; Engineering (Cyber Security) at NFSU, applicants are suggested to visit the official website of the university or can call the university helpline/ admission helpline. The cutoff is usually released as per the JEE Mains scores. The minimum eligibility requirement for admissions to BTech courses at NFSU is that applicants must complete their Class 12 from Science stream with an aggregate of 60%. Further, those who qualify for the minimum criteria should secure valid scores in JEE Mains too.&nbsp;</p>

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