In how many ways can a team of 11 players get selected from 25 if 6 of them are always included and 5 of them are always excluded?

I think, this is a trick question. If 5 of them are always excluded, then we have to select 11 from 20. Now, 6 are to be always included. So, we include them and are left to select 5 people from 14. Number of possible ways is 14C5 = 2002.