My self Abhishek , I am interested to join to pset University for BTech in computer science .How much kcet rank is required to get a free se
Second pu in progress I likely join to university for 2022
13 Views|Posted 4 years ago
Asked by Abhishek
1 Answer
T
Answered by
2 years ago
For general category students, the minimal cutoff for admission to PES University is 94746 to get a free se and also this is the best university which a good records of placements which can give you a better life style.
Similar Questions for you
Listed below are the top KCET accepting BTech colleges in Mysore with their tuition fees -
| Top Colleges | Tuition Fee |
|---|---|
| The National Institute of Engineering | INR 2.83 Lacs - INR 5.16 lakh |
| JSS Science and Technology University | INR 3.86 Lacs - INR 10.46 lakh |
| Vidyavardhaka College of Engineering | INR 3.86 Lacs - INR 14 lakh |
| ATME College of Engineering | INR 3.86 Lacs - INR 7.44 lakh |
| University of Mysore | INR 21,400 |
The KCET 2026 registration deadline for the BE/BTech programme has been extended to 22nd February. The KCET exam 2026 will be held on 23rd April and 24th April.
The annual family income must be below INR 8 Lacs to claim the EWS reservation benefits.
Economically Weaker Sections (General Merit only) are allocated a 10% reservation in KCET.
Yes, if their parents declared Karnataka as their hometown when joining the service.
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