My self Abhishek , I am interested to join to pset University for BTech in computer science .How much kcet rank is required to get a free se
Asked about PES University - B.Tech. in Computer Science and Engineering
Second pu in progress I likely join to university for 2022
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1 Answer
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For general category students, the minimal cutoff for admission to PES University is 94746 to get a free se and also this is the best university which a good records of placements which can give you a better life style.
Similar Questions for you
No. The official authority does not release mock tests. Candidates need to refer to third party websites for the mock tests.
No. The JEE Mains emphasizes on deep knowledge and quote challenging with negative marking whereas KCET is moderately difficult which emphasizes on direct factual questions with no negative markings.
The difficulty level for mathematics is considered as moderate to difficult and other subjects are considered as easier to moderate.
The exam tests knowledge of 11th and 12th syllabus so it is important to focus on 11th and 12th standard NCERT textbooks which gradually start by practicing previous years papers and appearing for mock examinations.
It is important to give mock tests for candidates appearing for KCET examination as it provides a holistic view and it provides a realistic exam experience also helping the candidates for analysing strengths and working on weaknesses.
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