My self Abhishek , I am interested to join to pset University for BTech in computer science .How much kcet rank is required to get a free se

Second pu in progress I likely join to university for 2022

15 Views|Posted 4 years ago
Asked by Abhishek
1 Answer
T
3 years ago
For general category students, the minimal cutoff for admission to PES University is 94746 to get a free se and also this is the best university which a good records of placements which can give you a better life style.

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Similar Questions for you

KCET is the main entrance exam for state quota seats. If you have a good JEE Main score, you can also apply for a management or NRI quota seat, or apply through COMEDK, which is another popular option in Karnataka. Each college may accept a different mix, so check individually.

For the General AI category, the maximum PES ECE cutoff 2026 acceptable for admission in the first round was 1223. So, students with a rank lower than 1223 can easily gain admission to the above-mentioned course. To know the maximum rank required by other categories, see the table below.

Category (All India)PES ECE cutoff 2026
General1223 
ST7369
PWD224168
Category (Home State)PES ECE cutoff 2026
General2193

KEA usually conducts multiple rounds of counselling, including Round 1, Round 2, and an Extended Round, depending on how many vacant seats are available.

Cutoff marks for KCET 2026 are calculated on the basis of number of applicants, availability of seats, performance of the candidates in the test, reservation and difficulty of the question paper.

Candidates who have passed or are due to pass class 12 (equivalent) in the specified subjects are eligible to apply for KCET 2026 as per the criteria of KEA.

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