On what basis does the CHARUSAT offer admission to the B.Tech. in Electronics and Communication Engineering course?
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1 Answer
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CHARUSAT offers admission to the B.Tech. in Electronics and Communication Engineering course based on the candidate's performance in the entrance exams such as JEE Main or GUJCET.
Similar Questions for you
In order to determine which is better for a BA between CHARUSAT and Marwadi University, candidates can compare based on their specialisation, seat intake, fees, cutoffs, etc. A comparison of the two universities for their BA courses on different parameters, including seat intake, fees, and ratings, is presented here:
Particular | BA at CHARUSAT | BA at Marwadi University |
---|---|---|
Tuition Fee | INR 1.44 Lacs to INT 1.92 lakh | INR 1.4 lakh |
Seat Intake | 380 | - |
Overall Shiksha Rating | 4.4/5 | 4.1/5 |
NOTE: The above-mentioned information is taken from their respective official sources. They are still subject to change and, hence, are indicative.
Unfortunately no, you need to achieve a higher rank according to the merit list to be able to get admission in charusat.
You can try in other field in charusat also.
Candidates who wish to enroll in the university's BTech programme must meet the requirements for admission. Charotar University of Science and Technology admits students based on their entrance. Students must take the recognised admission exams, such as GUJCET and JEE Main. Passing Class 12 with a minimum cumulative score of 45% from an approved board is the prerequisite. Therefore, if you match the above-mentioned admission requirements, you can apply for the CHARUSAT BTech course even if your Class 12 exam result was below 70%.
Chandubhai S Patel Institute of Technology GUJCET Cutoff 2024 was released for Round 3. THe Cutoff was released for different categories under the AI and the HS quota. For the General AI category, the cutoff rank ranged between 1831 and 34418. For the Home State category, the cutoff ranks ranged between 2438 and 13863. Therefore, it is possible to get into CHARUSAT with 25000 rank.
Chandubhai S Patel Institute of Technology cutoff 2024 for the B.E courses at the undergraduate level has been released for Round 1. The GUJCET cutoff 2024 required for the admission ranged between 2356 and 9587 for General AI students. For BTech in CSE, the required rank is 2356. The Chandubhai S Patel Institute of Technology CSE cutoff 2024 varies from the previous two years, indicating a fluctuating trend in the closing ranks. The Round 1 cutoff for this course was 1871 in 2023 and, 2176 in 2022. For more information, candidates can click here.
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