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Class 11thElectrochemistryChemistryNcert Solutions Chemistry Class 11th

1 mole of K2Cr2O7 cannot oxidise

Option 1 - <p>3.6 moles of FeSO₄ to Fe₂(SO₄)₃<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>1 mole of FeSO₄ to Fe₂(SO₄)₃<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>1.8 moles of Sn²⁺ to Sn⁴⁺<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>4 moles of Sn²⁺ to Sn⁴⁺</p>
5 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago
Correct Option - 4
Detailed Solution:

Meq of K? Cr? O? is greater than all the other given species.

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20mL of 0.02 M hypo solution is used for the titration of 10mL of copper sulphate solution, in the presence of excess of KI using starch as an indicator. The molarity of Cu2+ is found to be__________× 10-2 M. [nearest integer]

Given: 2Cu2+ + 4I- ® Cu2I2 + I2

 I2 + <!-- [if gte mso 9]><xml> </xml><![endif]-->  2 S 2 O 3 2 − → 2 I − + S 4 O 6 2 −

AK
Alok Kumar Singh

meq  of  l2=meq  of  Na2S2O3=20×0.002×1

2 × mmol of l2 = 0.4

mmol of l2 = 0.2 mmol

mmol of Cu2+ = 0.2 × 2 × 10-3

[ C u 2 + ] = 0 . 4 × 1 0 − 3 1 0 × 1 0 − 3 = 0 . 0 4 = 4 × 1 0 − 2 M

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Chemistry Ncert Solutions Class 11th 2023

Chemistry Ncert Solutions Class 11th 2023

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