200ml of 0.5M solution of CuBr2 was electrolysed using Pt as electrodes with a current of 0.965 ampere in one hour, what is the normality of the remaining CuBr2 solution assuming no change in volume?
200ml of 0.5M solution of CuBr2 was electrolysed using Pt as electrodes with a current of 0.965 ampere in one hour, what is the normality of the remaining CuBr2 solution assuming no change in volume?
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Answered by
5 months ago
Initial m equivalent of Cu²? = 200 * 0.5 * 2 = 200 m eq
So electricity passed = (0.965*3600)/96500 = 36 * 10? ³ eq. = 36 m eq
m eq CuBr? remaining = 200 – 36 = 164 ∴ N = meq / V (in ml) = 164/200 = 0.82
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Chemistry Ncert Solutions Class 11th 2023
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