A cannot engine works as a refrigerator between $250 K$ and $300 K$ . It receives $500 c a l$ heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is nearly

Option 1 - <math> <mn>420</mn> <mi> </mi> <mi>J</mi> </math>

Option 2 - <math> <mn>2100</mn> <mi> </mi> <mi>J</mi> </math>

Option 3 - <math> <mn>772</mn> <mi> </mi> <mi>J</mi> </math>

Option 4 - <math> <mn>2520</mn> <mi> </mi> <mi>J</mi> </math>

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Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 1

Detailed Solution:

$C O P = \frac{Q_{t}}{W} = \frac{T_{l o w}}{T_{h i g h} - T_{l o w}} = \frac{250}{300 - 250} = 5$

$\frac{Q_{L}}{W} = 5$

$W = \frac{500 * 4.2}{5} 420 J$

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A cannot engine works as a refrigerator between 250 K and 300 K . It receives 500 c a l heat from the reservoir at the lower temperature. The amount of work done in each cycle to operate the refrigerator is nearly

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