A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity 4 m s - 1 . The ball strikes the water surface after 4 s . The height of bridge above water surface is (Take g = 10 m s - 2  ):


Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mn>68</mn> <mtext> </mtext> <mi mathvariant="normal">m</mi> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mn>56</mn> <mtext> </mtext> <mi mathvariant="normal">m</mi> </math> </span></p>
Option 3 - <p><sup><span class="mathml" contenteditable="false"> <math><mn>60</mn> <mi mathvariant="normal">m</mi></math> </span></sup></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mn>64</mn> <mtext> </mtext> <mi mathvariant="normal">m</mi> </math> </span></p>
5 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 4
Detailed Solution:

Let height of bridge = h

Displacement of ball, S = - h

S = u t + 1 2 a t 2 - h = 4 * 4 + 1 2 ( - 10 ) ( 4 ) 2 h = 64 m

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Physics Motion in Straight Line 2025

Physics Motion in Straight Line 2025

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