A light wave travelling linearly in a medium of dielectric constant 4, incidents on the horizontal interface separating medium with air. The angle of incidence for which the total intensity of incident wave will be reflected back into the same medium will be:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>1</mn> <mn>0</mn> <mo>°</mo> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>2</mn> <mn>0</mn> <mo>°</mo> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>3</mn> <mn>0</mn> <mo>°</mo> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>6</mn> <mn>0</mn> <mo>°</mo> </mrow> </math> </span></p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 3
Detailed Solution:

Velocity of light in medium 2

  = 1 μ m m

v 2 = 1 μ 0 μ r 0 r

= 1 1 * μ 0 0 * 4

v 2 = 1 2 μ 0 0

By snell's law for total internal Reflection

μ 2 s i n θ C > μ 1 s i n 9 0 °

θ c > 3 0 °

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Physics Ray Optics and Optical Instruments 2021

Physics Ray Optics and Optical Instruments 2021

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