A sphere of mass 2 kg and radius 0.5 m is rolling with an initial speed of 1 ms?¹ goes up an inclined plane which makes an angle of 30° with the horizontal plane, without slipping. How long will the sphere take to return to the starting point A?

 

Option 1 - <p>0.60 s<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>0.57 s</p>
Option 3 - <p>0.52 s<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>0.80 s</p>
6 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago
Correct Option - 2
Detailed Solution:

The acceleration 'a' is calculated as:
a = (g sinθ) / (1 + I/mr²) = (10 * sin30°) / (1 + 2/5) = 25/7 m/s²
The time 't' is calculated as:
t = 2v / a = (2 * 1) / (25/7) = 0.57 s

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Physics Work, Energy and Power 2021

Physics Work, Energy and Power 2021

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