Complex A has a composition of H??O?Cl?Cr. It has green colour. A 0.2M solution of complex when treated with excess of AgNO? gave 57.45gm of white precipitate. The formula of the complex would be: [Given: at mass Cr = 52amu, Cl = 35.5amu, Ag = 107.8amu ]

Option 1 - <p>[Cr(H₂O)₆]Cl₃<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>[CrCl(H₂O)₅]Cl₂·H₂O<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>[CrCl₂(H₂O)₄]Cl·2H₂O</p>
Option 4 - <p>[Cr(H₂O)₃Cl₃]</p>
5 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 2
Detailed Solution:

 0.2 mole gives 0.4  mole of  A g C l (moles of A g C l = 57.45 143 = 0.4  )

1 mole complex gives 0.4 0.2 = 2  moles A g C l

The correct answer should be 2 nd    option.

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Chemistry Coordination Compounds 2025

Chemistry Coordination Compounds 2025

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