ΔH_f° of CO₂(g), CO(g), N₂O(g) and NO₂(g) in kJ mol⁻¹ respectively is -393, -110, 81 and 34. Calculate the ΔH in kJ for the following reaction :
2NO₂(g) + 3CO(g) → N₂O(g) + 3CO₂(g).
ΔH_f° of CO₂(g), CO(g), N₂O(g) and NO₂(g) in kJ mol⁻¹ respectively is -393, -110, 81 and 34. Calculate the ΔH in kJ for the following reaction :
2NO₂(g) + 3CO(g) → N₂O(g) + 3CO₂(g).
ΔH_rxn = ΔH_f (N? O, g) + 3ΔH_f (CO? , g) – (2ΔH_f NO? , g) – 3ΔH_f (CO, g)
= 81 + 3* (– 393) – 2 * 34 – 3 (–110)
= 81 – 1179 – 68 + 330 = – 836 kJ
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