For a chemical reaction X -> P, the rate of reaction doubles when the concentration of X is increased 4 times. The order of reaction with respect to X is

Option 1 - <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math>

Option 2 - <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> </mrow> </math>

Option 3 - 1

Option 4 - Zero

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Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 1

Detailed Solution:

$r_{1} = k {[x]}^{n}$ … (i)

$2 r_{1} = k {[4 x]}^{n}$ … (ii)

$(i i) \div (i)$

$\Rightarrow \frac{2 r_{1}}{r_{1}} = \frac{k {[4 x]}^{n}}{k {[x]}^{n}}$

$\Rightarrow 2 = {(2)}^{2 n}$

$\Rightarrow n = \frac{1}{2}$

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