For the reaction C?H? → C?H? + H? the reaction enthalpy ?rH = ____ kJ mol?¹. (Round off to the nearest integer).
[ Given: Bond enthalpies in kJ mol?¹ : C-C: 347, C=C:611; C-H:414,H-H:436]
For the reaction C?H? → C?H? + H? the reaction enthalpy ?rH = ____ kJ mol?¹. (Round off to the nearest integer).
[ Given: Bond enthalpies in kJ mol?¹ : C-C: 347, C=C:611; C-H:414,H-H:436]
For the reaction C? H? → C? H? + H? , calculate the enthalpy change (ΔH).
ΔH = [Bond energy (C-C) + 6 * Bond energy (C-H)] - [Bond energy (C=C) + 4 * Bond energy (C-H) + Bond energy (H-H)]
ΔH = 347 + 2 (414) - 611 - 436 = 128 kJ/mol.
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