If the solubility product of AB₂ is 3.20 * 10⁻¹¹ M³, then the solubility of AB₂ in pure water is _____ * 10⁻⁴ mol L⁻¹. [Assuming that neither kind of ion reacts with water]
If the solubility product of AB₂ is 3.20 * 10⁻¹¹ M³, then the solubility of AB₂ in pure water is _____ * 10⁻⁴ mol L⁻¹. [Assuming that neither kind of ion reacts with water]
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5 months ago
(x/m) = k (P)¹/?
log (x/m) = log k + (1/n) log P
Slope = 1/n = 2 So n = ½
Intercept ⇒ log k = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3 [0.04]² = 48 * 10?
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