In a series LCR circuit, the inductance $L$ is $10\mathrm{m}\mathrm{H}$ , capacitance $\mathrm{C}$ is $1\mu \mathrm{F}$  and resistance $\mathrm{R}$ is $100\mathrm{\Omega }$ . The frequency at which resonance

Capacitive reactance $=\frac{1}{\omega \mathrm{C}}={\mathrm{X}}_{\mathrm{c}}$ (say) on decreasing the operating frequency $\omega$  reduces

As $X_c$ is inversely proportional to $\omega$ the value of $X_c$  increase

$\therefore {\mathrm{I}}_{\mathrm{C}}={\mathrm{I}}_{\mathrm{D}}$

$=\frac{{\mathrm{V}}_{\mathrm{o}}}{{\mathrm{X}}_{\mathrm{c}}}$

As ${\mathrm{X}}_{\mathrm{c}}$  increases, therefore displacement current Id decreases.