In the given figure, the block of mass m is dropped from the point 'A'. The expression for kinetic energy of block when it reaches point 'B' is
In the given figure, the block of mass m is dropped from the point 'A'. The expression for kinetic energy of block when it reaches point 'B' is
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mi>m</mi> <mi>g</mi> <mtext> </mtext> <mtext> </mtext> <msubsup> <mrow> <mi>y</mi> </mrow> <mrow> <mn>0</mn> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mi>m</mi> <mi>g</mi> <mtext> </mtext> <mtext> </mtext> <msup> <mrow> <mi>y</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> </mrow> </math> </span></p>
Option 3 - <p>mg (y – y<sub>0</sub>) </p>
Option 4 - <p>mg y<sub>0</sub></p>
1 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
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Answered by
4 months ago
Correct Option - 4
Detailed Solution:
According to conservation of energy, we can write
Gain in kinetic energy = Loss in potential energy
=>Kf – Kin = Uin - Uf
=>K - = mgy – mg (y – y0) = mgy0
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Physics Work, Energy and Power 2021
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