Let M=[0αα0], where is a non-zero real number an N=k=149M2k. If (I – M2)N = 2I, then the positive integral value of is

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10 months ago

N=M2+M4+.....+M98

=(α2I)+(α2I)2+....+(α2I)49

=I(α2+α4α6+....α98)

N = I(α2α4+α6.......+α98)

=Iα2(1(α2)49)1(α2)

N = Iα2(1+α98)1+α2

Now (Im2)N=2I

(I+α2I)(Iα2(1+α98)1+α2=2I

? α100 + α2 = 2

? α = ±1

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Maths NCERT Exemplar Solutions Class 12th Chapter Four 2025

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