Let the lines (2 – i) z = (2 + i) (here i2 = -1) be normal to a circle C. If the line iz + is tangent to this circle C, then its radius is:
Let the lines (2 – i) z = (2 + i) (here i2 = -1) be normal to a circle C. If the line iz + is tangent to this circle C, then its radius is:
(2 – i) z = (2 + i) , put z = x + iy
(ii)
x + 2y = 2
(iii)
Equation of tangent x – y + 1 = 0
Solving (i) and (ii)
Perpendicular distance of point from x – y + 1 = 0 is p = r
Similar Questions for you
f (x) = λ (x-2)²
⇒ 12 = λ (2)² ⇒ λ = 3
f (x) = 3 (x-2)² f (6) = 3 × 4² = 48
Kindly consider the following figure
->Represent a circle
->Represent a line X – y
So max |z + 1|2 = AQ2
Hence α + β) = 48
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Maths Ncert Solutions class 12th 2026
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