Let U(i=1 to n)Xᵢ = U(i=1 to 50)Yᵢ = T, where each Xᵢ contains 10 elements and each Yᵢ contains 5 elements. If each element of the set T is an element of exactly 20 of sets Xᵢ 's and exactly 6 of sets Yᵢ 's then n is equal to:
Let U(i=1 to n)Xᵢ = U(i=1 to 50)Yᵢ = T, where each Xᵢ contains 10 elements and each Yᵢ contains 5 elements. If each element of the set T is an element of exactly 20 of sets Xᵢ 's and exactly 6 of sets Yᵢ 's then n is equal to:
Option 1 - <p>15</p>
Option 2 - <p>30</p>
Option 3 - <p>45</p>
Option 4 - <p>50</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
Answered by
5 months ago
Correct Option - 2
Detailed Solution:
Let number of elements in T is R.
∴ 20R = 500 ⇒ R = 25
and 6R = 5N ⇒ N = 30
Similar Questions for you
max {n (A), n (B)} ≤ n (A U B) ≤ n (U)
⇒ 76 ≤ 76 + 63 - x ≤ 100
⇒ -63 ≤ -x ≤ -39
⇒ 63 ≥ x ≥ 39
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...
Didn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering
