On balancing the given redox reaction, aCr₂O₇²⁻(aq) + bSO₃²⁻(aq) + cH⁺(aq) → 2aCr³⁺(aq) + bSO₄²⁻(aq) + c/2H₂O(l) the coefficients a, b and c are found to be, respectively:
On balancing the given redox reaction, aCr₂O₇²⁻(aq) + bSO₃²⁻(aq) + cH⁺(aq) → 2aCr³⁺(aq) + bSO₄²⁻(aq) + c/2H₂O(l) the coefficients a, b and c are found to be, respectively:
Reduction half reaction.
Cr? O? ²? + 14H? + 6e? → 2Cr? ³ + 7H? O
Oxidation half reaction
SO? ²? + H? O → SO? ²? + 2e? ] * 3
Oxygen is balanced by adding water and hydrogen is balanced by adding H? and the charge is balanced by electrons.
Add ( eq. (i) + (3 * eq. (ii) )
Cr? O? ²? + 3SO? ²? + 8H? → 2Cr? ³ +
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Chemistry Ncert Solutions Class 12th 2023
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