Right option for the number of tetrahedral and octahedral voids in hexagonal primitive unit cell are :
Right option for the number of tetrahedral and octahedral voids in hexagonal primitive unit cell are :
Option 1 - <p>8,4<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>6,12<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>2,1<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>12,6</p>
1 Views|Posted 5 months ago
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1 Answer
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Answered by
5 months ago
Correct Option - 4
Detailed Solution:
No. of atoms in Hexagonal primitive unit cell = 6
No. of Tetrahedral voids = 2 * No. of atoms per unit cell
= 2 * 6 = 12
No. of Octahedral voids = No. of atoms per unit cell = 6
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