A body of man 100 kg travelled 10 m before coming to rest. If m = 0.4, work done against friction is (motion is happening on horizontal surface, take g=10 m/s2)

Option 1 - <p><span lang="EN-IN">4500 J</span></p>
Option 2 - <p><span lang="EN-IN">5000 J</span></p>
Option 3 - <p><span lang="EN-IN">4200 J</span></p>
Option 4 - <p><span lang="EN-IN">4000 J</span></p>
4 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
A
4 months ago
Correct Option - 4
Detailed Solution:

  v 2 2 a = s (a = mg)

v2 = 2 * mgs

v2 = 2 * (0.4) * 10 * 10

v2 = 80

Wf = Dk

= 1 2 * 1 0 0 * 8 0  

Wf = – 4000

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Physics Work, Energy and Power 2021

Physics Work, Energy and Power 2021

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